Optimal. Leaf size=701 \[ -\frac {c^2 d e (1-3 n) (1-n) x^{n+1} \, _2F_1\left (1,\frac {n+1}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{4 a^3 n^2 (n+1) \left (a e^2+c d^2\right )^2}+\frac {c (1-4 n) (1-2 n) x \left (c d^2-a e^2\right ) \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{8 a^3 n^2 \left (a e^2+c d^2\right )^2}+\frac {2 c^2 d e^3 (1-n) x^{n+1} \, _2F_1\left (1,\frac {n+1}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a^2 n (n+1) \left (a e^2+c d^2\right )^3}-\frac {c e^2 (1-2 n) x \left (3 c d^2-a e^2\right ) \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{2 a^2 n \left (a e^2+c d^2\right )^3}-\frac {c x \left ((1-4 n) \left (c d^2-a e^2\right )-2 c d e (1-3 n) x^n\right )}{8 a^2 n^2 \left (a e^2+c d^2\right )^2 \left (a+c x^{2 n}\right )}-\frac {6 c^2 d e^5 x^{n+1} \, _2F_1\left (1,\frac {n+1}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a (n+1) \left (a e^2+c d^2\right )^4}+\frac {c e^2 x \left (-a e^2+3 c d^2-4 c d e x^n\right )}{2 a n \left (a e^2+c d^2\right )^3 \left (a+c x^{2 n}\right )}+\frac {c x \left (-a e^2+c d^2-2 c d e x^n\right )}{4 a n \left (a e^2+c d^2\right )^2 \left (a+c x^{2 n}\right )^2}+\frac {6 c e^6 x \, _2F_1\left (1,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{\left (a e^2+c d^2\right )^4}+\frac {e^6 x \, _2F_1\left (2,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{d^2 \left (a e^2+c d^2\right )^3}+\frac {c e^4 x \left (5 c d^2-a e^2\right ) \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a \left (a e^2+c d^2\right )^4} \]
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Rubi [A] time = 0.69, antiderivative size = 701, normalized size of antiderivative = 1.00, number of steps used = 16, number of rules used = 5, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.238, Rules used = {1437, 245, 1431, 1418, 364} \[ -\frac {c^2 d e (1-3 n) (1-n) x^{n+1} \, _2F_1\left (1,\frac {n+1}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{4 a^3 n^2 (n+1) \left (a e^2+c d^2\right )^2}+\frac {2 c^2 d e^3 (1-n) x^{n+1} \, _2F_1\left (1,\frac {n+1}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a^2 n (n+1) \left (a e^2+c d^2\right )^3}+\frac {c (1-4 n) (1-2 n) x \left (c d^2-a e^2\right ) \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{8 a^3 n^2 \left (a e^2+c d^2\right )^2}-\frac {c e^2 (1-2 n) x \left (3 c d^2-a e^2\right ) \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{2 a^2 n \left (a e^2+c d^2\right )^3}-\frac {c x \left ((1-4 n) \left (c d^2-a e^2\right )-2 c d e (1-3 n) x^n\right )}{8 a^2 n^2 \left (a e^2+c d^2\right )^2 \left (a+c x^{2 n}\right )}-\frac {6 c^2 d e^5 x^{n+1} \, _2F_1\left (1,\frac {n+1}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a (n+1) \left (a e^2+c d^2\right )^4}+\frac {c e^4 x \left (5 c d^2-a e^2\right ) \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a \left (a e^2+c d^2\right )^4}+\frac {6 c e^6 x \, _2F_1\left (1,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{\left (a e^2+c d^2\right )^4}+\frac {e^6 x \, _2F_1\left (2,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{d^2 \left (a e^2+c d^2\right )^3}+\frac {c e^2 x \left (-a e^2+3 c d^2-4 c d e x^n\right )}{2 a n \left (a e^2+c d^2\right )^3 \left (a+c x^{2 n}\right )}+\frac {c x \left (-a e^2+c d^2-2 c d e x^n\right )}{4 a n \left (a e^2+c d^2\right )^2 \left (a+c x^{2 n}\right )^2} \]
Antiderivative was successfully verified.
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Rule 245
Rule 364
Rule 1418
Rule 1431
Rule 1437
Rubi steps
\begin {align*} \int \frac {1}{\left (d+e x^n\right )^2 \left (a+c x^{2 n}\right )^3} \, dx &=\int \left (\frac {e^6}{\left (c d^2+a e^2\right )^3 \left (d+e x^n\right )^2}+\frac {6 c d e^6}{\left (c d^2+a e^2\right )^4 \left (d+e x^n\right )}-\frac {c \left (-c d^2+a e^2+2 c d e x^n\right )}{\left (c d^2+a e^2\right )^2 \left (a+c x^{2 n}\right )^3}-\frac {c e^2 \left (-3 c d^2+a e^2+4 c d e x^n\right )}{\left (c d^2+a e^2\right )^3 \left (a+c x^{2 n}\right )^2}-\frac {c e^4 \left (-5 c d^2+a e^2+6 c d e x^n\right )}{\left (c d^2+a e^2\right )^4 \left (a+c x^{2 n}\right )}\right ) \, dx\\ &=-\frac {\left (c e^4\right ) \int \frac {-5 c d^2+a e^2+6 c d e x^n}{a+c x^{2 n}} \, dx}{\left (c d^2+a e^2\right )^4}+\frac {\left (6 c d e^6\right ) \int \frac {1}{d+e x^n} \, dx}{\left (c d^2+a e^2\right )^4}-\frac {\left (c e^2\right ) \int \frac {-3 c d^2+a e^2+4 c d e x^n}{\left (a+c x^{2 n}\right )^2} \, dx}{\left (c d^2+a e^2\right )^3}+\frac {e^6 \int \frac {1}{\left (d+e x^n\right )^2} \, dx}{\left (c d^2+a e^2\right )^3}-\frac {c \int \frac {-c d^2+a e^2+2 c d e x^n}{\left (a+c x^{2 n}\right )^3} \, dx}{\left (c d^2+a e^2\right )^2}\\ &=\frac {c x \left (c d^2-a e^2-2 c d e x^n\right )}{4 a \left (c d^2+a e^2\right )^2 n \left (a+c x^{2 n}\right )^2}+\frac {c e^2 x \left (3 c d^2-a e^2-4 c d e x^n\right )}{2 a \left (c d^2+a e^2\right )^3 n \left (a+c x^{2 n}\right )}+\frac {6 c e^6 x \, _2F_1\left (1,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{\left (c d^2+a e^2\right )^4}+\frac {e^6 x \, _2F_1\left (2,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{d^2 \left (c d^2+a e^2\right )^3}-\frac {\left (6 c^2 d e^5\right ) \int \frac {x^n}{a+c x^{2 n}} \, dx}{\left (c d^2+a e^2\right )^4}+\frac {\left (c e^4 \left (5 c d^2-a e^2\right )\right ) \int \frac {1}{a+c x^{2 n}} \, dx}{\left (c d^2+a e^2\right )^4}+\frac {\left (c e^2\right ) \int \frac {\left (-3 c d^2+a e^2\right ) (1-2 n)+4 c d e (1-n) x^n}{a+c x^{2 n}} \, dx}{2 a \left (c d^2+a e^2\right )^3 n}+\frac {c \int \frac {\left (-c d^2+a e^2\right ) (1-4 n)+2 c d e (1-3 n) x^n}{\left (a+c x^{2 n}\right )^2} \, dx}{4 a \left (c d^2+a e^2\right )^2 n}\\ &=\frac {c x \left (c d^2-a e^2-2 c d e x^n\right )}{4 a \left (c d^2+a e^2\right )^2 n \left (a+c x^{2 n}\right )^2}+\frac {c e^2 x \left (3 c d^2-a e^2-4 c d e x^n\right )}{2 a \left (c d^2+a e^2\right )^3 n \left (a+c x^{2 n}\right )}-\frac {c x \left (\left (c d^2-a e^2\right ) (1-4 n)-2 c d e (1-3 n) x^n\right )}{8 a^2 \left (c d^2+a e^2\right )^2 n^2 \left (a+c x^{2 n}\right )}+\frac {c e^4 \left (5 c d^2-a e^2\right ) x \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a \left (c d^2+a e^2\right )^4}+\frac {6 c e^6 x \, _2F_1\left (1,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{\left (c d^2+a e^2\right )^4}-\frac {6 c^2 d e^5 x^{1+n} \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a \left (c d^2+a e^2\right )^4 (1+n)}+\frac {e^6 x \, _2F_1\left (2,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{d^2 \left (c d^2+a e^2\right )^3}-\frac {c \int \frac {\left (-c d^2+a e^2\right ) (1-4 n) (1-2 n)+2 c d e (1-3 n) (1-n) x^n}{a+c x^{2 n}} \, dx}{8 a^2 \left (c d^2+a e^2\right )^2 n^2}-\frac {\left (c e^2 \left (3 c d^2-a e^2\right ) (1-2 n)\right ) \int \frac {1}{a+c x^{2 n}} \, dx}{2 a \left (c d^2+a e^2\right )^3 n}+\frac {\left (2 c^2 d e^3 (1-n)\right ) \int \frac {x^n}{a+c x^{2 n}} \, dx}{a \left (c d^2+a e^2\right )^3 n}\\ &=\frac {c x \left (c d^2-a e^2-2 c d e x^n\right )}{4 a \left (c d^2+a e^2\right )^2 n \left (a+c x^{2 n}\right )^2}+\frac {c e^2 x \left (3 c d^2-a e^2-4 c d e x^n\right )}{2 a \left (c d^2+a e^2\right )^3 n \left (a+c x^{2 n}\right )}-\frac {c x \left (\left (c d^2-a e^2\right ) (1-4 n)-2 c d e (1-3 n) x^n\right )}{8 a^2 \left (c d^2+a e^2\right )^2 n^2 \left (a+c x^{2 n}\right )}+\frac {c e^4 \left (5 c d^2-a e^2\right ) x \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a \left (c d^2+a e^2\right )^4}-\frac {c e^2 \left (3 c d^2-a e^2\right ) (1-2 n) x \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{2 a^2 \left (c d^2+a e^2\right )^3 n}+\frac {6 c e^6 x \, _2F_1\left (1,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{\left (c d^2+a e^2\right )^4}-\frac {6 c^2 d e^5 x^{1+n} \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a \left (c d^2+a e^2\right )^4 (1+n)}+\frac {2 c^2 d e^3 (1-n) x^{1+n} \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a^2 \left (c d^2+a e^2\right )^3 n (1+n)}+\frac {e^6 x \, _2F_1\left (2,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{d^2 \left (c d^2+a e^2\right )^3}+\frac {\left (c \left (c d^2-a e^2\right ) (1-4 n) (1-2 n)\right ) \int \frac {1}{a+c x^{2 n}} \, dx}{8 a^2 \left (c d^2+a e^2\right )^2 n^2}-\frac {\left (c^2 d e (1-3 n) (1-n)\right ) \int \frac {x^n}{a+c x^{2 n}} \, dx}{4 a^2 \left (c d^2+a e^2\right )^2 n^2}\\ &=\frac {c x \left (c d^2-a e^2-2 c d e x^n\right )}{4 a \left (c d^2+a e^2\right )^2 n \left (a+c x^{2 n}\right )^2}+\frac {c e^2 x \left (3 c d^2-a e^2-4 c d e x^n\right )}{2 a \left (c d^2+a e^2\right )^3 n \left (a+c x^{2 n}\right )}-\frac {c x \left (\left (c d^2-a e^2\right ) (1-4 n)-2 c d e (1-3 n) x^n\right )}{8 a^2 \left (c d^2+a e^2\right )^2 n^2 \left (a+c x^{2 n}\right )}+\frac {c e^4 \left (5 c d^2-a e^2\right ) x \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a \left (c d^2+a e^2\right )^4}+\frac {c \left (c d^2-a e^2\right ) (1-4 n) (1-2 n) x \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{8 a^3 \left (c d^2+a e^2\right )^2 n^2}-\frac {c e^2 \left (3 c d^2-a e^2\right ) (1-2 n) x \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{2 a^2 \left (c d^2+a e^2\right )^3 n}+\frac {6 c e^6 x \, _2F_1\left (1,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{\left (c d^2+a e^2\right )^4}-\frac {6 c^2 d e^5 x^{1+n} \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a \left (c d^2+a e^2\right )^4 (1+n)}-\frac {c^2 d e (1-3 n) (1-n) x^{1+n} \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{4 a^3 \left (c d^2+a e^2\right )^2 n^2 (1+n)}+\frac {2 c^2 d e^3 (1-n) x^{1+n} \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a^2 \left (c d^2+a e^2\right )^3 n (1+n)}+\frac {e^6 x \, _2F_1\left (2,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{d^2 \left (c d^2+a e^2\right )^3}\\ \end {align*}
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Mathematica [A] time = 0.70, size = 426, normalized size = 0.61 \[ \frac {x \left (-\frac {2 c^2 d e x^n \left (a e^2+c d^2\right )^2 \, _2F_1\left (3,\frac {n+1}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a^3 (n+1)}+\frac {c \left (c d^2-a e^2\right ) \left (a e^2+c d^2\right )^2 \, _2F_1\left (3,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a^3}-\frac {4 c^2 d e^3 x^n \left (a e^2+c d^2\right ) \, _2F_1\left (2,\frac {n+1}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a^2 (n+1)}+\frac {c e^2 \left (3 c d^2-a e^2\right ) \left (a e^2+c d^2\right ) \, _2F_1\left (2,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a^2}-\frac {6 c^2 d e^5 x^n \, _2F_1\left (1,\frac {n+1}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a (n+1)}+\frac {e^6 \left (a e^2+c d^2\right ) \, _2F_1\left (2,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{d^2}+\frac {c e^4 \left (5 c d^2-a e^2\right ) \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a}+6 c e^6 \, _2F_1\left (1,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )\right )}{\left (a e^2+c d^2\right )^4} \]
Antiderivative was successfully verified.
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fricas [F] time = 2.91, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {1}{a^{3} e^{2} x^{2 \, n} + 2 \, a^{3} d e x^{n} + a^{3} d^{2} + {\left (c^{3} e^{2} x^{2 \, n} + 2 \, c^{3} d e x^{n} + c^{3} d^{2}\right )} x^{6 \, n} + 3 \, {\left (a c^{2} e^{2} x^{2 \, n} + 2 \, a c^{2} d e x^{n} + a c^{2} d^{2}\right )} x^{4 \, n} + 3 \, {\left (a^{2} c e^{2} x^{2 \, n} + 2 \, a^{2} c d e x^{n} + a^{2} c d^{2}\right )} x^{2 \, n}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (c x^{2 \, n} + a\right )}^{3} {\left (e x^{n} + d\right )}^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.23, size = 0, normalized size = 0.00 \[ \int \frac {1}{\left (e \,x^{n}+d \right )^{2} \left (c \,x^{2 n}+a \right )^{3}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ {\left (c d^{2} e^{6} {\left (7 \, n - 1\right )} + a e^{8} {\left (n - 1\right )}\right )} \int \frac {1}{c^{4} d^{10} n + 4 \, a c^{3} d^{8} e^{2} n + 6 \, a^{2} c^{2} d^{6} e^{4} n + 4 \, a^{3} c d^{4} e^{6} n + a^{4} d^{2} e^{8} n + {\left (c^{4} d^{9} e n + 4 \, a c^{3} d^{7} e^{3} n + 6 \, a^{2} c^{2} d^{5} e^{5} n + 4 \, a^{3} c d^{3} e^{7} n + a^{4} d e^{9} n\right )} x^{n}}\,{d x} - \frac {2 \, {\left (a c^{3} d^{2} e^{4} {\left (11 \, n - 1\right )} + c^{4} d^{4} e^{2} {\left (3 \, n - 1\right )} - 4 \, a^{2} c^{2} e^{6} n\right )} x x^{4 \, n} + {\left (a^{2} c^{2} d e^{5} {\left (8 \, n - 1\right )} + 2 \, a c^{3} d^{3} e^{3} {\left (5 \, n - 1\right )} + c^{4} d^{5} e {\left (2 \, n - 1\right )}\right )} x x^{3 \, n} + {\left (a^{2} c^{2} d^{2} e^{4} {\left (34 \, n - 3\right )} - c^{4} d^{6} {\left (4 \, n - 1\right )} - 2 \, a c^{3} d^{4} e^{2} {\left (n + 1\right )} - 16 \, a^{3} c e^{6} n\right )} x x^{2 \, n} + {\left (a^{3} c d e^{5} {\left (10 \, n - 1\right )} + 2 \, a^{2} c^{2} d^{3} e^{3} {\left (7 \, n - 1\right )} + a c^{3} d^{5} e {\left (4 \, n - 1\right )}\right )} x x^{n} + {\left (a^{3} c d^{2} e^{4} {\left (10 \, n - 1\right )} - a c^{3} d^{6} {\left (6 \, n - 1\right )} - 12 \, a^{2} c^{2} d^{4} e^{2} n - 8 \, a^{4} e^{6} n\right )} x}{8 \, {\left (a^{4} c^{3} d^{8} n^{2} + 3 \, a^{5} c^{2} d^{6} e^{2} n^{2} + 3 \, a^{6} c d^{4} e^{4} n^{2} + a^{7} d^{2} e^{6} n^{2} + {\left (a^{2} c^{5} d^{7} e n^{2} + 3 \, a^{3} c^{4} d^{5} e^{3} n^{2} + 3 \, a^{4} c^{3} d^{3} e^{5} n^{2} + a^{5} c^{2} d e^{7} n^{2}\right )} x^{5 \, n} + {\left (a^{2} c^{5} d^{8} n^{2} + 3 \, a^{3} c^{4} d^{6} e^{2} n^{2} + 3 \, a^{4} c^{3} d^{4} e^{4} n^{2} + a^{5} c^{2} d^{2} e^{6} n^{2}\right )} x^{4 \, n} + 2 \, {\left (a^{3} c^{4} d^{7} e n^{2} + 3 \, a^{4} c^{3} d^{5} e^{3} n^{2} + 3 \, a^{5} c^{2} d^{3} e^{5} n^{2} + a^{6} c d e^{7} n^{2}\right )} x^{3 \, n} + 2 \, {\left (a^{3} c^{4} d^{8} n^{2} + 3 \, a^{4} c^{3} d^{6} e^{2} n^{2} + 3 \, a^{5} c^{2} d^{4} e^{4} n^{2} + a^{6} c d^{2} e^{6} n^{2}\right )} x^{2 \, n} + {\left (a^{4} c^{3} d^{7} e n^{2} + 3 \, a^{5} c^{2} d^{5} e^{3} n^{2} + 3 \, a^{6} c d^{3} e^{5} n^{2} + a^{7} d e^{7} n^{2}\right )} x^{n}\right )}} - \int -\frac {{\left (8 \, n^{2} - 6 \, n + 1\right )} c^{4} d^{6} + {\left (32 \, n^{2} - 18 \, n + 1\right )} a c^{3} d^{4} e^{2} + {\left (48 \, n^{2} - 2 \, n - 1\right )} a^{2} c^{2} d^{2} e^{4} - {\left (24 \, n^{2} - 10 \, n + 1\right )} a^{3} c e^{6} - 2 \, {\left ({\left (3 \, n^{2} - 4 \, n + 1\right )} c^{4} d^{5} e + 2 \, {\left (7 \, n^{2} - 8 \, n + 1\right )} a c^{3} d^{3} e^{3} + {\left (35 \, n^{2} - 12 \, n + 1\right )} a^{2} c^{2} d e^{5}\right )} x^{n}}{8 \, {\left (a^{3} c^{4} d^{8} n^{2} + 4 \, a^{4} c^{3} d^{6} e^{2} n^{2} + 6 \, a^{5} c^{2} d^{4} e^{4} n^{2} + 4 \, a^{6} c d^{2} e^{6} n^{2} + a^{7} e^{8} n^{2} + {\left (a^{2} c^{5} d^{8} n^{2} + 4 \, a^{3} c^{4} d^{6} e^{2} n^{2} + 6 \, a^{4} c^{3} d^{4} e^{4} n^{2} + 4 \, a^{5} c^{2} d^{2} e^{6} n^{2} + a^{6} c e^{8} n^{2}\right )} x^{2 \, n}\right )}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {1}{{\left (a+c\,x^{2\,n}\right )}^3\,{\left (d+e\,x^n\right )}^2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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